Question

23. The sum of the numerator and denominator of a fraction is 4 more than
twice the numerator. If the numerator and denominator are increased
by 3, they are in the ratio 2:3. Determine the fraction. (CBSE 2010]
​

Answer 1

Answer:

11/15

x - y = 4

3x - 2y = -3

Thus you have to equate acc. to the conditions and evaluate.

x is the NUMERATOR; y is the DENOMINATOR

Answer 2

let the numerator be x

x + denominator = 2x + 4

denominator = x + 4

if increased by 3 the fraction is

x + 3/x + 7

it is given that they are in the ratio 2:3

therefore 2 (x +3) = 3 (x+7)

2x + 6 = 3x + 21

x = -15

the fraction is 15/11