Question

23. The volume of 0.1 M Ca(OH), needed for the
neutralization of 40 ml of 0.05 M oxalic acid is
(1) 10 ml
(2) 20 ml
(3) 30 ml
(4) 40 ml
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Answer 1

Answer:

Explanation:

Dilution law: M1V1=M2V2

0.1V1=40*0.05

0.1V1=2

Therefore V1=20ml

Answer 2

Answer: N1V1 = N2V2

Explanation:

0.2xv =0.1 x40

V = 4/0.2 =20 ml