Question

23. There are chits numbered 1 to 20 in a box.
One chit is drawn at random. Find the
probability that the number on the chit is
( 1 ) an odd number, (2) a prime number,
(3) is a multiple of 5.​

Answer 1

Answer:

Step-by-step explanation:

Total no. of numbered chits:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20

Total no. of events = 20

1. An odd number

  Odd no.s = 1, 3, 5, 7, 9, 11, 13, 15, 17, 19

  Total no. of favourable events = 10

  Probability = total no. favourable of events / total no.of events

  P(E) = 10/20 = 1/2

2. Prime no.s = 2, 3, 5, 7, 9, 11, 13, 17, 19

   Total no.of favorable events = 9

   P(E) = 9/20

3. Multiples of 5 = 5, 10, 15, 20

   Total no. of favourable events = 4

    P(E) = 4/20 = 1/5

Answer 2

Answer:

(1) 1/2 , (2) 9/20 , ( 3) 1/5