Question

23 times a certain number is as much above 14 as 16 is above 7 times the number. Find the number?

Answer 1

Answer:

$let \: the \: required \: nu. = x \\ so \: according \: to \: the \: que \\ 23x - 14 = 16 - 7x \\ = 23 x + 7x = 16 + 14 \\ = 30x = 30 \\ = x = \frac{30}{30} \\ = x = 1 \: \: ans \\ \\ hence \: the \: required \: num \: is \: 1.$