23.Triangle ABE and triangle CDE are *
equal
congruent
similar
no relation
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Given
Given,
△ABE≅△ACD
Hence , AB =AC ……………..by CPCT (1)
and AE =AD …………….by CPCT
=> AD=AE ………….(2)
Dividing (2) & (1)
AD/AB = AE/AC …………(3)
In △ADE and △ABC
∠A=∠A (common angle)
AD\AB = AE/ AC from (3)
∴△ADE is similar to △ABC by SAS criterion.
Hence it is proved that both are similar .
Given,
△ABE≅△ACD
Hence , AB =AC ……………..by CPCT (1)
and AE =AD …………….by CPCT
=> AD=AE ………….(2)
Dividing (2) & (1)
AD/AB = AE/AC …………(3)
In △ADE and △ABC
∠A=∠A (common angle)
AD\AB = AE/ AC from (3)
∴△ADE is similar to △ABC by SAS criterion.
Hence it is proved that both are similar .
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