Question

23. Two charges + 3.2x10-1°C and - 3.2x10-19
placed at 2.4A
apart form an electric dipole. It is
placed in a uniform electric field of intensity
4x10 volt/m. The electric dipole-moment is
1) 15.36 x 10-coulomb x m
2) 15.36 x 10-'%coulomb x m
3) 7.68 x 10-coulomb x m
4) 7.68 x 10-'coulomb x m​

Answer 1

Answer:

electric dipole(p) = distance × q

Explanation:

p = 2.4 ×10^-10 × 3.2 ×10^-19

= 7.68× 10^-9