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Two concentric thin metallic spheres of
radii R, and R, (R, >R) bear charges Qi
and Q, respectively. Then the potential
at radius r between R, and R, will be 1/
(41E.) times of
Answers
Answered by
1
Answer:
Explanation:
q1+q2r
q1r1+q2r
q1r2+q2r2
q1r2+q2r1
Answer :
B
Solution :
The given point is inside the larger swphere. So, potential at this point is the same as no the surface of the pshere. The value is 14πε0q1r1.
The given point is outside the smaller sphere. So, the charge on the smaller sphere would behave as if concentrated at the centre. the potential due to
smaller sphere is 14πε0q2r.
Applying principle of superposition of potentials, the
total potential is 14πε0[q1r1+q2r]
i hope this answer will help you
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