Question

23. Two objects of masses m: and m2 having the same size are dropped simultaneously from
heights h: and he respectively. Find out the ratio of time they would take in reaching the ground.
Will this ratio remain the same if () one of the objects is hollow and the other one is solid and (ii)
both of them are hollow, size remaining the same in each case. Give reason.​

Answer 1

Answer:-

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Answer 2

Explanation:

We know that 

v=u+at

Here v=0 and a=g

so 0=u+gt

u=−gt --- (i) 

we also know 

v2.u2=2as   ---(ii)

Here v=0,u=−gt from eqn (i) and S=h1 and taking t=t1

putting all above values in eq (ii)

g2t12=2gh1

or 

h1=21gt12  ----(iii)

Similarly for S=h2 and t=t2

h2=21gt22    ----(iv)

Dividing eqn (iii) & (iv) we get,

t2t1=h2h1

The ratio will not change in either case because acceleration remains the same. In the case of free-fall acceleration does not depend upon mass and size of the body.

Answer