23. Two trains of length 125 meters and 115 meters are running on parallel tracks. When they run in the same direction the faster train crosses the slower train in
when they run in opposite direction they cross each other in 10 seconds. What is the speed of each train?
O 15,8
16,9
None of these
O 16,8
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Answer:
Let the speed of second train is = x km/hr time =l1+l2Relative speed in oppo. direction
6=(125+125)(65+x)×518
6=(250×18)(65+x)×5
65+x=50×3
x=150−65
x=85 km/hr
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Let the speed of faster train = X m/sec
Let the speed of slower train= Y m/sec
Then, relative speed when they are moving in opposite direction = X + Y
Apti Problem on trains 69
10X + 10Y = 240
X + Y = 24
Y = 24 − X ................ (1)
Relative speed when they are moving in same direction = X − Y
Apti Problem on trains 70
30X − 30Y = 240
3X − 3Y = 24
X − Y = 8 ............... (2)
Put the value of Y from equation (1) to equation (2)
X − (24 − X) = 8
X − 24 + X = 8
2X = 8 + 24
2X = 32
X = 16 m/sec
Put the value of X in equation (1) to find value of Y;
Y = 24-16 = 8 m/sec.
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