Question

23 ) What is the current Flow in the bulb?
P = 550 watts
R = 22 Ohms
| = Amps | बल्ब में धारा का प्रवाह कितना है?
= 550 Ohms
V = 22 Volts
1 =
Amps​

Answer 1

Given:

The values given in the question are:

Power $=P=550$ watts

Resistance $=R = 22$ ohms

To find:

We need to find the amount of current flow through the bulb.

Solution:

We know that, in electricity, $P=I^2R$.

Where is $P$ the power, $R$ is the Resistance and $I$ is the current.

We have the values of power and resistance.

So, we can substitute the values of power and resistance in the above formula and find the value of current.

$\Rightarrow P=I^2R$

$\Rightarrow \frac{P}{R} =I^2$

$\Rightarrow I^2= \frac{P}{R}$

Taking square root on both sides,

$\Rightarrow \sqrt{I^2} = \sqrt{\frac{P}{R} }$

$\Rightarrow I = \sqrt{\frac{P}{R} }$

Now, substitute the values of power and resistance.

$\Rightarrow I = \sqrt{\frac{550}{22} }$

$\Rightarrow I = \sqrt{25 }$

$\Rightarrow I = 5$ Amps

Therefore, the current flow through the bulb is $5$ Amps.

Answer 2

Answer:

Step-by-step explanation: