Question

23. What is the speed of light in glycerin (n = 1.47) expressed in terms of the speed of light in a vacuum ?
(1) 2.040
(B) 1.47c
(C) 0.680​

Answer 1

Answer:

given,

n=1.47

we know that speed of light in vaccum=3×10^8m/s

n= speed of light in vacuum/ speed of light in glycerin

1.47=3×10^8/speed of light in glycerin

1.47/3×10^8=speed if light in glycerin

147/3×100×10^8= speed if light in glycerin

49/100×10^8= speed of light in glycerin

0.49×10^-8m/s = speed of light in glycerin

that's solve

Answer 2

Answer:

In unit of c speed of light in glycerine is = 0.680

Explanation:

Speed of light in vaccum is = c = $3*10^8 ms^{-1}$

Speed of light in a given medium of refractive index '$n$' is = $\frac{c}{n}$

Given:

Refractive index of glycerine = $n=1.47$

Therefore, speed of light in glycerine = $\frac{c}{1.47} = 0.680*c$

In unit of c speed of light in glycerine is = 0.680

$\therefore$ option (c) is correct

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