23. When air of density 1.3 kg/m flows across the top of the tube shown in the accompanying figure, water
rises in the tube to a height of 1.0 cm. What is the speed of the air ?
1.0 cm
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The speed of the air is V = 12.4 m/s
Explanation:
1 / 2ρair v2 = ρwghw
V = √ 2ρwghw / ρ (air)
V = √ 2 x 10^3 x 10 x 10^-2 / 1.3
V = 12.4 m/s
Thus the speed of the air is V = 12.4 m/s
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