Question

(23_x),(40_x)=(57_x),(108_x)​

Answer 1

Answer:

Step-by-step explanation:

let no to be subtracted be x

then,

(23-x) : (40-x) = (57-x) : (108-x)

                                          After transposing

(23-x) (108-x ) = (57-x) (40-x)

2484-23x-108x-x^2 = 2280-57x-40x-x^2

             x^2 gets cancelled from both the sides

2484-131x = 2280-97x

2484-2280 = -97x + 131x

204=34x

204/34=x

    204/34 gets divided and become 6

6=x