2304 is. this is a prfect cube
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2304 is a not a Perfect Cube. Because There is no number Which multiplied by itself to get 2304.
Cube Root of 2304 is
![\sqrt[3]{2304} \\ \sqrt[3]{ {4}^{3} \times 36} \\ \sqrt[3]{ {4}^{3}} \sqrt[3]{36} \\ 4 \sqrt[3]{36} = 13.20771](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B2304%7D++%5C%5C++%5Csqrt%5B3%5D%7B+%7B4%7D%5E%7B3%7D++%5Ctimes+36%7D+%5C%5C++%5Csqrt%5B3%5D%7B+%7B4%7D%5E%7B3%7D%7D+++%5Csqrt%5B3%5D%7B36%7D++%5C%5C+4+%5Csqrt%5B3%5D%7B36%7D+++%3D+13.20771 "\sqrt[3]{2304} \\ \sqrt[3]{ {4}^{3} \times 36} \\ \sqrt[3]{ {4}^{3}} \sqrt[3]{36} \\ 4 \sqrt[3]{36} = 13.20771")
I Hope It will help you
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2304 is a not a Perfect Cube. Because There is no number Which multiplied by itself to get 2304.
Cube Root of 2304 is
I Hope It will help you
#behappy
#Keepstudying
Answered by
2
2304 is a perfect square number but not a perfect cube.
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