Question

232
422
А
B
312
Р
3. In the circuit diagram, calculate:
(a) effective resistance
(6) potential difference between points A and B and
points B and C
(c) current through branch AC and PQ
[Ans. (a) 2 2, (b) 2 V,4 V, (c) Iac = 1 A, 1pq = 2 A]
4. In the circuit diagram, calculate:
6V​

Answer 1

Answer:

Effective Resistance = 2 ohms.

Potential Difference between A and B = 2 volts

Potential Difference between B and C = 4 volts

Current through Branch AC = 1 amp

Current through Branch PQ = 2 amp

Explanation:

Resistance (R)

Current (I)

Potential Difference (V)

Effective Resistance = R

For the series AB and BC

r(ac) = r(ab) + r(bc)r(ac)=r(ab)+r(bc)

2 \: ohms + 4 \: ohms = 6 \: ohms2ohms+4ohms=6ohms

For the pareller AC and PQ

\frac{1}{r} = \frac{1}{r(ac)} + \frac{1}{r(pq)}

r

1

=

r(ac)

1

+

r(pq)

1

\begin{gathered}\frac{1}{r} = ( \frac{1}{6} + \frac{1}{3} ) = \frac{1}{2} \\ r = 2\end{gathered}

r

1

=(

6

1

+

3

1

)=

2

1

r=2

R = 2 ohms.

Remaining explanation will be given later since a little busy

Answer 2

$\huge\red{Answer!}$

•

Effective Resistance = 2 ohms.

•

Potential Difference between A and B = 2 volts

•

Potential Difference between B and C = 4 volts

•

Current through Branch AC = 1 amp

•

Current through Branch PQ = 2 amp

Explanation:

Resistance (R)

Current (I)

Potential Difference (V)

Effective Resistance = R

For the series AB and BC

r(ac) = r(ab) + r(bc)

$2 \: ohms + 4 \: ohms = 6 \: ohms$

For the pareller AC and PQ

$\frac{1}{r} = \frac{1}{r(ac)} + \frac{1}{r(pq)}$

$\begin{gathered}\frac{1}{r} = ( \frac{1}{6} + \frac{1}{3} ) = \frac{1}{2} \\ r = 2\end{gathered}$

R = 2 ohms.