Question

23328 state which of the following are perfect cubes using the method of prime factorisation

Answer 1

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Answer 2

factorize 23328.
2 |23328
2 |11664
2 |5832
2 |2916
2 |1458
3 |729
3 |243
3 |81
3 |27
3 |9
3 |3
|1 so 23328=2×2×2×2×2×3×3×3×3×3×3=>
$23328 = {2}^{5} \times {3}^{6} \:$
so it cannot be a perfect cube. I hope it helps you...