Question

234.2 gm of sugar syrup contains 34.2 gm of sugar .what is the molal concentration of the solution

Answer 1

The molal concentration of the sugar syrup solution is 0.5mol/kg.

Given:

• Sugar syrup solution in which solute is sugar (Molecular mass = 342.3g) whereas solvent is syrup.
• Weight of solute = 34.2g
• Weight of the solvent = 234.2g

To find:

Molality concentration of the sugar syrup = ?

Formula to be used:

Grams to mole conversion

• Moles = $\frac{Given mass}{Molecular mass}$

Molal concentration calculation

• Molal concentration = $\frac{Solute (moles)}{Solvent (kg)}$

Calculation:

• To find molal concentration, value of the solute must be in moles and the value of solvent must be in kilograms.
• As in the question,both the mass of solute and solvent are  given in grams, it must be converted into moles and kilogram respectively.
• Accordingly using the gram to mole conversion formula, it gives:

Moles = $\frac{Given mass}{Molecular mass}$

Moles of solute = $\frac{34.2}{342.3}$

Moles of solute = 0.09

• 234.2 g is equal to 0.2342 kg
• Substituting the obtained value in molal concentration formula, it gives:

Molal concentration = $\frac{Solute (moles)}{Solvent (kg)}$

Molal concentration = $\frac{0.09 moles}{0.2342 kg}$

Molal concentration = 0.5 mol/kg

Conclusion:

The molal concentration of the sugar syrup solution is calculated as 0.5mol/kg.

Learn more about molal concentration

A solution of sulfuric acid with molal concentration of 8.01m has density of 1.354g/ml what is molarity of solution

https://brainly.in/question/5890472

What is molality concentration ​

https://brainly.in/question/9784923