2352 is equal to 2 the power x into 3 power Y into 70 power Z then X + Y + Z is equal to
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According to the question, we have
2352 = 2 to power x × 3 to power y × 7 to power z
Or
2352 = 2^x + 3^y + 7^z .............. (1)
The prime factorization of 2352 gives us
2352 = 2 × 2 × 2 × 2 × 3 × 7 × 7
2353 = 2^4 + 3^1 + 7^2 ............. (2)
Comparing (1) and (2) , we have
2^x + 3^y + 7^z = 2^4 + 3^1 + 7^2
So we have
x = 4 , y = 1 , z = 2
so we have
x + y + z = 4 + 1 + 2
x + y + z = 7 is the required Answer.
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