Question

- 239 kJ mol-1
AH = - 393 +21286) - - 726) kJ mol-1
Q. 6.15. Calculate the enthalpy change for the process
Given : Avap
Hº (CCI)
= 30-5 kJ mol-, 4, Hº (CCI) = - 135-5 kJ mol-1
4. Hº (C12) = 242 kJ mol-1.
Ans
CCl4 (g)
-C (g) + 4 Cl (g) and calculate bond enthalpy of C-Clince
4 Å° (C) = 715-0 kJ mol-1 where Á, Hº is enthalpy of atomisation​

Answer 1

Answer:

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