Question

23g of Na contains 6.022X10 23
ałoms, how
atomi are present in 46g of sodium?)
many​

Answer 1

Answer:

12.044×10^23

Hope this helps......

Answer 2

Answer:

Twice of the Avagardro's constant.(2×6.022×10²³ atoms)

Explanation:

A mole contains 6.022×10²³ atoms.

Molar mass is the mass of a mole of an atom. One mole of sodium contains 23 gms.

So 46g of sodium must contain twice of a mole i.e 2×6.022×10²³ atoms