Question

23g of sodium will react with ethyl alcohol to give?

Answer 1

When Sodium reacts with ethyl alcohol, the reaction taking place is : C2H5OH + Na → C2H5ONa + 1/2H2 The products formed will be sodium ethanoate and hydrogen.

Answer 2

Explanation:

$2Na+2C_2H_5OH\rightarrow 2C_2H_5ONa+H_2$

Moles of sodium = $\frac{23 g}{23 g/mol}=1 mol$

According to reaction , 2 moles of sodium reacts with 2 moles of ethyl alcohol to give 2 moles of sodium ethoxide and 1 mole of hydrogen gas.

1) Then 1 mol of sodium will react with :

$\frac{2}{2}\times 1= 1 mol$ ethyl alchol

Mass of 1 moles ethyl alchol:

$1 mol\times 46 g/mol=46 g$

2)According to reaction , 2 moles of sodium gives 2 moles of sodium ethoxide .

Then 1 mol of sodium will give with :

$\frac{2}{2}\times 1= 1 mol$ sodium ethoxide

Mass of 1 moles sodium ethoxide:

$1 mol\times 68 g/mol=68 g$

3 )According to reaction , 2 moles of sodium gives 1 mole of hydrogen gas.

Then 1 mol of sodium will give with :

$\frac{1}{2}\times 1= 0.5 mol$ hydrogen gas

Mass of 0.5 moles of hydrogen gas:

$0.5 mol\times 2 g/mol=1.0 g$