23rd term of arithmetic sequence is 32 and 35th term is 104.which is the middle term of first 35 terms of this sequence
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6
Answer will be -132 it is correct
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18
Given:
a+22d=32
a+34d=104
Subtracting both the equations we get:
12d=72
d=6
Substituting value of d in any of the equation we get a= -100
In the first 35 terms , 18th term will be the middle most term...
a+(n-1)d = a18
-100 + 102
2 is the middle most term.
a+22d=32
a+34d=104
Subtracting both the equations we get:
12d=72
d=6
Substituting value of d in any of the equation we get a= -100
In the first 35 terms , 18th term will be the middle most term...
a+(n-1)d = a18
-100 + 102
2 is the middle most term.
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