23x-29y=98,29x-23y=110
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Hey !!!
23x - 29y = 98 ------1)
29x - 23y = 110 --------1)
Adding 1st both equation ..
23x - 29y = 98
29x - 23y = 110
_____________
52x - 52y = 208
52 (x - y ) = 208
x - y = 208/52 = 4
x - y = 4 --------3 )
After that substracting equation 1st from 2nd
29 x- 23y = 110
23x - 29 y = 98
-___+______-
_____________
6x+ 6y = 12
6 ( x + y ) = 12
x + y = 12/6
x + y = 2 -------------4)
after all add both 3 and 4 tha equation ..
x - y = 4
x + y = 2
_______
2x = 6
x = 3
. substitute the value of x on 3rd equation ..
x - y = 4
3 - y = 4
-y = 4 - 3
y = -1
x = 3 and y = - 1
________________________
Hope it helps you !!!
@Rajukumar1111
23x - 29y = 98 ------1)
29x - 23y = 110 --------1)
Adding 1st both equation ..
23x - 29y = 98
29x - 23y = 110
_____________
52x - 52y = 208
52 (x - y ) = 208
x - y = 208/52 = 4
x - y = 4 --------3 )
After that substracting equation 1st from 2nd
29 x- 23y = 110
23x - 29 y = 98
-___+______-
_____________
6x+ 6y = 12
6 ( x + y ) = 12
x + y = 12/6
x + y = 2 -------------4)
after all add both 3 and 4 tha equation ..
x - y = 4
x + y = 2
_______
2x = 6
x = 3
. substitute the value of x on 3rd equation ..
x - y = 4
3 - y = 4
-y = 4 - 3
y = -1
x = 3 and y = - 1
________________________
Hope it helps you !!!
@Rajukumar1111
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