Question

23x-29y=98,29x-23y=110

Answer 1

Hey !!!

23x - 29y = 98 ------1)
29x - 23y = 110 --------1)

Adding 1st both equation ..

23x - 29y = 98
29x - 23y = 110
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52x - 52y = 208

52 (x - y ) = 208

x - y = 208/52 = 4

x - y = 4 --------3 )

After that substracting equation 1st from 2nd

29 x- 23y = 110
23x - 29 y = 98
-___+______-
_____________
6x+ 6y = 12

6 ( x + y ) = 12

x + y = 12/6

x + y = 2 -------------4)

after all add both 3 and 4 tha equation ..

x - y = 4
x + y = 2
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2x = 6
x = 3
. substitute the value of x on 3rd equation ..

x - y = 4
3 - y = 4

-y = 4 - 3

y = -1

x = 3 and y = - 1
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Hope it helps you !!!

@Rajukumar1111