Question

23x-29y=98, 29x-23y=110
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Answer 1

Answer:

23x−29y=98⟶(i)

29x−23y=110⟶(ii)

Adding (i) and (ii) we get ,

52x−52y=208

⇒52(x−y)=208

⇒x−y=4⟶(iii)

Substracting (ii) from (i),

−6x−6y=−12

⇒x+y=2⟶(iv)

Now by solving (iii) and (iv),

2x=6

⇒x=3

Substituting value of x in equation (iv),

3+y=2

y=−1

∴x=3 and y=−1

Step-by-step explanation:

23x−29y=98⟶(i)

29x−23y=110⟶(ii)

Adding (i) and (ii) we get ,

52x−52y=208

⇒52(x−y)=208

⇒x−y=4⟶(iii)

Substracting (ii) from (i),

−6x−6y=−12

⇒x+y=2⟶(iv)

Now by solving (iii) and (iv),

2x=6

⇒x=3

Substituting value of x in equation (iv),

3+y=2

y=−1

∴x=3 and y=−1