Math, asked by vandana249, 4 months ago

23xy-46+54y-108 factorise form

Answers

Answered by shindetanmay282

Step-by-step explanation:

We have

23xy−46x+54y−108

Factoring out 23 from the first two terms and 54 from the last two,

=23x(y−2)+54(y−2)

Now, factoring out (y−2),

=(23x+54)(y−2)

∴23xy−46x+54y−108=(23x+54)(y−2)

Hence, is correct.

shindetanmay282: prove then you are not giving proper answer and telling me

samridhsemwal1000: but there is only 46 not 46x

samridhsemwal1000: see carefully

samridhsemwal1000: yes the question could be wrong i also thought that

samridhsemwal1000: but according to that question my is right

vandana249: s samridhsemwal is right

shindetanmay282: si what happen you can change it but i have given you step to solve na

samridhsemwal1000: pls mark my answer as brainlist

vandana249: ss both are correct

vandana249: ok

Answered by samridhsemwal1000

Answer:

23(xy-2) +54(y-2)

Step-by-step explanation:

Have a great day

pls mark as brainlist

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