Question

.24
146. Out of the following, which weighs
the maximum ?
(A) 2.24 litres of CO2 at N. T. P.
(B) 6.022 x 1023 molecules of CO2
(©) 6.022 x 1023 atoms of carbon
(D) 10 grams of carbondioxide (CO,​

Answer 1

Answer:

(c) is the right answer

Answer 2

Answer:

B) 6.022 × 10²³ molecules of CO₂ weighs the most.

Explanation:

Correct answer:

(b) 6.022×10²³

• Given: No. of molecules of CO₂= 6.022×10²³

• We know that: 6.022×10²³ molecules are equal to 1 mole, Molar mass of CO₂= 12.01+(16×2)= 44.01 grams [∵ Molar mass of C= 12.01gram, molar mass of O= 16gram)

Now, mass of CO₂= NO. of mole × molar mass of CO₂

⇒mass of CO₂= 1 × 44.01grams

                        = 44.01grams

(A) 2.24 litres of CO₂ at N.T.P.

• Given: volume of CO₂ at N.T.P.= 2.24 Litres
• We know that: at N.T.P. volume of 1 mole CO₂= 22.4 litres

Now, no. of mole present in 2.24 litres of CO₂= $\frac{2.24}{22.4}$= 0.1 mole of CO₂

∴ Mass of 0.1 mole CO₂= 0.1 × molar mass of CO₂

                                      = 0.1 × 44.01 grams = 4.401 grams

(C) 6.022 × 10²³ atoms of Carbon

as we already 6.022× 10²³ atoms= 1 mole atoms of Carbon's mass= 12.01 grams

(D)10 grams of Carbon dioxide (CO₂)

So, among all the masses (B) 6.022×10²³ molecules of CO₂ weighs the most= 44.01grams.

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