(2⁴×2⁵)÷2⁸ Evaluate class7
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_____________________________
The answer is -: 2
_____________________________
Step by Step Explanation-:
The laws that we had applied are -:
1) (a^m x a^n ) = a^m +n
2) (a^m ÷ a^n) ⇒ a ^m-n
____________________________
Given ,
(2⁴×2⁵)÷2⁸
To evaluate-:
(2⁴×2⁵)÷2⁸
First ,
According to the BODMAS
First , We will solve the brackets
The law which we are going to apply-:
(a^m x a^n ) = a^m +n
⇒ (2^4 x 2^5) ÷ 2^8
⇒(2^4 + 5) ÷ 2^8
⇒ (2^9) ÷ 2^8
Now second law that we are going to
apply is -:
(a^m ÷ a^n)
⇒ a ^m-n
⇒ 2^9 ÷ 2^8
⇒ 2^9-8
⇒ 2^1
⇒ 2
Hence ,
⇒ (2^4 x 2^5) ÷ 2^8
= 2
The answer is -: 2
_______________________________
_____________________________
The answer is -: 2
_____________________________
Step by Step Explanation-:
The laws that we had applied are -:
1) (a^m x a^n ) = a^m +n
2) (a^m ÷ a^n) ⇒ a ^m-n
____________________________
Given ,
(2⁴×2⁵)÷2⁸
To evaluate-:
(2⁴×2⁵)÷2⁸
First ,
According to the BODMAS
First , We will solve the brackets
The law which we are going to apply-:
(a^m x a^n ) = a^m +n
⇒ (2^4 x 2^5) ÷ 2^8
⇒(2^4 + 5) ÷ 2^8
⇒ (2^9) ÷ 2^8
Now second law that we are going to
apply is -:
(a^m ÷ a^n)
⇒ a ^m-n
⇒ 2^9 ÷ 2^8
⇒ 2^9-8
⇒ 2^1
⇒ 2
Hence ,
⇒ (2^4 x 2^5) ÷ 2^8
= 2
The answer is -: 2
_______________________________
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