Question

24
37
37
12
th
7
X
(iv)
Fig 6.29
EXERCISE 6.5
1. PQR is a triangle, right-angled at P. If PQ = 10 cm
and PR = 24 cm, find QR.​

Answer 1

Answer:

26

Step-by-step explanation:

lenth of QR is 26

found by pythagorous theorm

Answer 2

Answer:

26

Step-by-step explanation:

by using phytahgoreus theorem

AB^2+BC^2=AC^2

HERE

A=R

B=P

C=Q

NOW PUT THE VALUEE

RP^2+PQ^2=QR^2

10^2+24^2=QR^2

100+576=QR^2

676=QR^2

NOW BRING THE SQUARE TO THE LHS

ROOT 676=QR

26=QR

SO,THE VALUE OF QR IS 26

HOPE YOU GOT IT

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