{24√3x^3}-{125y^3}=?
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Q: 24√3 x^3 - 125y^3
=( 2√3x )^3 - (5y )^3
use identiy:
a^3 - b^3 = (a - b ) ( a^2 + ab + b^2 )
here , a = 2√3 x , b = 5y
therefore ,
(2√3x )^3 - (5y)^3=
(2√3x-5y)
{(2√3x)^2+(2√3x)(5y)+(5y)^2 }
=(2√3x - 5y) ( 12x^2 + 10√3xy + 25y^2 )
=( 2√3x )^3 - (5y )^3
use identiy:
a^3 - b^3 = (a - b ) ( a^2 + ab + b^2 )
here , a = 2√3 x , b = 5y
therefore ,
(2√3x )^3 - (5y)^3=
(2√3x-5y)
{(2√3x)^2+(2√3x)(5y)+(5y)^2 }
=(2√3x - 5y) ( 12x^2 + 10√3xy + 25y^2 )
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