Question

24 a ^3 + 81 b ^3 solve

Answer 1

$<b >Hey here is your answer$

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$= 24 {a}^{3} + 81 {b}^{3} \\ \\ = 3(8 {a}^{3} + 27 {b}^{3} ) \\ \\ =3[(2a {)}^{3} + (3b {)}^{3} ]$

using identity :-

$= {a}^{3} + {b}^{3} = (a + b)( {a}^{2} + {b}^{2} - ab) \\ \\ = 3(2a + 3b)[ {(2a)}^{2} + {(3b)}^{2} - 2a \times 3b)] \\ \\ = 3(2a + 3b)[ {4a}^{2} + {9b}^{2} - 6ab)]$

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hope this helps you

### BE BRAINLY ###

Answer 2

Hi ,

24a³ + 81b³

= 3( 8a³ + 27b³ )

= 3[ ( 2a )³+ ( 3b )³ ]

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we know the algebraic identity:

x³ + y³ = (x+y)(x² - xy + y² )

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= 3( 2a+3b)[(2a)² -(2a)(3b)+(3b)²]

=3(2a+3b)(4a² - 6ab + 9b² )

I hope this helps you.

: )