Question

24. (a) A cube of side 5 cm is immersed in water and then in saturated salt solution. In which case
will it experience a greater buoyant force. If each side of the cube is reduced to 4 cm and then
immersed in water, what will be the effect on the buoyant force experienced by the cube as
compared to the first case for water. Give reason for each case.
(b) A ball weighing 4 kg of density 4000 kg mis completely immersed in water of density 10 kg
Find the force of buoyancy on it. (Given g = 10 m s.)
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Answer 1

Answer:

1=

b'

Buoyant force, F = V×ρ×g

(where, ρ = Density of water, V = Volume of water displaced by the body)

Buoyant force depends upon volume and density, since, saturated salt solution have higher density than the water. So, in saturated solution, cube will experience a greater buoyant force. 

2= Buoyancy force can be calculated with the equation Fb=Vs×D×g, where Fb is the buoyancy force, Vs is the submerged volume, D is the density of the fluid the object is submerged in, and g is the force of gravity. 

In this case, the weight of the ball is 4 kg and the density of the ball is 

4000kg/m3. Therefore the volume is given as V=dm=40004m3. Substituting the given values in the equation, we get,

Fb=VsDg=40004m3×1000 kg/m3×10m/s2=10 N.

Hence, the force of buoyancy is 10 N.

Explanation:

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Answer 2

Explanation:

Buoyant force, F = V×ρ×g

(where, ρ = Density of water, V = Volume of water displaced by the body)

Buoyant force depends upon volume and density, since, saturated salt solution have higher density than the water. So, in saturated solution, cube will experience a greater buoyant force. 

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