24/a-b+28/a+b=6
30/a-b+21/a+b=13/2
Answer.
Let 1/a-b=x and 1/a+b=y
24x+28y=6 ( i )
30x+42y=13/2
60x+42y=13 (ii)
(i) and (ii) second by substitution method.
24x+28y=6
24x=6-28y
x=6-28y/24 (iii)
(iii) equation put in (ii) equation.
60x+42y=13
60(6-28y/24) +42y=13
360-1680y+1008y=312
-672y = -48
y=1/14(iv)
(iv) equation put in (iii) equation.
x=6-28y/24
x=6-28(1/14) /24
x=4/24
x=1/6
put the value of x and y.
1/a-b=x
1/a-b=1/6
a-b=6(v)
1/a+b=y
1/a+b=1/14
a+b=14(vi)
Elimination method btw (v) and (vi)
a-b=6
a+b=14
________
b=4
__________
put the value of b in (vi)
a-b=6
a-4=6
a=10
a=10, b=4
Answers
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Answer:
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Answer:
omg itna big question.
Step-by-step explanation:
asked with your teacher
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