Question

24.
A body of mass 5 Kg, initially at rest,
is moved by a horizontal force of 2 N on a
smooth horizontal surface. Find the work done by the force in 10s?
A. 40 J
D. 20 J
B. 30 J
E. 10 J
C. 50 J

Answer 1

Answer:

work done is force into displacement

F=ma

2=5×a

2/5=a

s=1/2at²

s=1/2×2/5×100

200/10

20

s=20

w=f×s

2×20

40j