Math, asked by chandanapriya2312, 4 months ago

24. A cab driver covers a distance between A and B at a speed of 40 km/h and on the return his speed is 60 km/h. He goes again from A to B at thrice the original speed that of from A to B. Now, he starts from B to C with the average speed of the journey till now, with its speed increasing every hour by 5 km/h. After how many hours his speed will reach 100 km/h??
8 hours
4 hours
12 hours
9 hours​

Answers

Answered by RvChaudharY50
31

Solution :-

Let us assume that, the distance from A to B is 120 km.

so,

→ Time taken from A to B = Distance/speed = 120/40 = 3 hours.

→ Time taken from B to A = D/S = 120/60 = 2 hours.

again,

→ Time taken from A to B = D/(3 * speed from A to B) = 120/(3 * 40) = 120/120 = 1 hour.

then,

→ Average speed till now = (Total distance covered)/(Total time taken) = (120 + 120 + 120) / (3 + 2 + 1) = 360/6 = 60 km/h .

Now,

→ speed from B to C in first hour = 60 km/h .

→ speed in second hour = 65 km/h .

A/q,

→ a + (n - 1)d = an

→ 60 + (n - 1)5 = 100

→ 60 + 5n - 5 = 100

→ 55 + 5n = 100

→ 5n = 100 - 55

→ 5n = 45

→ n = 9 hours. (Ans.)

Hence, After 9 hours his speed will reach 100 km/h.

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