Question

24. A car covers 60 m in 4 second and covers 40 m in 6 seconds. The average velocity of car is A) 20m/s B) 10 m/s C) 60 m/s D) 40 m/s

Answer 1

Given :

➨ A car covers first 60m distance in 4s and second 40m distance in 6s.

To Find :

➠ Average velocity of car.

SoluTion :

➾ Average velocity is defined as the ratio of total displacement to the total time taken.

➾ It is a vector quantity having both magnitude as well as direction.

➾ It can be positive, negative or zero.

➾ SI unit : m/s

$\longrightarrow\tt\:v_{av}=\dfrac{d_1+d_2}{t_1+t_2}\\ \\ \longrightarrow\tt\:v_{av}=\dfrac{60+40}{4+6}\\ \\ \longrightarrow\tt\:v_{av}=\dfrac{100}{10}\\ \\ \longrightarrow\underline{\boxed{\bf{v_{av}=10\:ms^{-1}}}}$

Option B is correct.

Answer 2

▪ Question -

A car covers 60m in 4 sec & second car covers 40m in 6 sec.

▪ To Find -

Average Velocity of car.

▪ Answer -

$⟹av = \frac{60 + 40}{6 + 4}$

$⟹av = \frac{100}{10}$

$⟹av = \frac{\cancel{100}}{\cancel{10}}$

$⟹av = {10ms}^{ - 1}$

So, Option B is correct.