Question

24. A car moves with a speed of 72
km/h for 15 minutes and then with
a speed of 108 km/h for the next 15
min. Calculate the total distance
covered by the car?​

Answer 1

Explanation:

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Answer 2

$d = \frac{speed}{time} \\ d = \frac{72}{ \frac{15}{60}h } \\ d = \frac{72 \times 60}{15} \\ d = 72 \times 4 \\ d = 288km \\ \\ \\ \\ \\ \\ {d }^{2} = \frac{108}{ \frac{15}{60}h } \\ {d}^{2} = \frac{108 \times 60}{15} \\ {d}^{2} = 108 \times 4 \\ {d}^{2} = 424km \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ total \: distance \: = {d}^{1} + {d}^{2} \\ = (288 + 424)km \\ = 712km$

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