Question

24. A charge of 6 uC experiences a force of 0.24 N in an electric field. The potential gradient at this
point is
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Answer 1

Answer:

$\\\tt = 0.04 \times 10^{-60} \dfrac{V}{m}$

Explanation:

Potential gradient is given by:

$\\\tt \dfrac{N}{q} = \dfrac{0.24 N}{6 \times 10^{-6}C} = 0.04 \times 10^{-6} \dfrac{V}{m}$