Question

24. A falling stone takes 0.2 seconds to fall past a window which is 1m high. From how far above the
top of the window was the stone dropped is am here x =​

Answer 1

Answer:0.78m

Explanation:

Answer 2

Let,

u=initial velocity of the stone

h=height above the window

s=height of the window

v0=initial velocity of the stone when it passes by the window

t=time taken to pass by the window

g=acceleration due to gravity (10m/s2)

The stone will begin with initial velocity 0 m/s.

Using 3rd equation of motion,

v02 = 2gh+u2

v0= \sqrt{2gh}

Now, using second equation of motion for motion of the stone when it passes by the window.

s=v0t+ ½ gt2

\sqrt{2gh} t= s – ½ gt2

(Squaring both sides)

2ght2 = (s – ½ gt2)2

Substituting the given values,

2x10xh x 0.04 = (1 – ½ x10x 0.04 )2

0.8h = (0.64)2

So, h = 0.8 m

Please mark as brainliest