24.A fully charged capacitor has a capacitance C.It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity s and mass m.If the temperature of the block is raised by Delta T,the potential difference V across the capacitance is
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The electrical potential energy stored in the capacitor is = C V² /2
This energy is dissipated in the circuit through the resistance wire. That heat is absorbed by the insulated block. Apply conservation of energy :
Heat absorbed = m s ΔT = C V² /2
=> V = √[2 m s ΔT / C]
This energy is dissipated in the circuit through the resistance wire. That heat is absorbed by the insulated block. Apply conservation of energy :
Heat absorbed = m s ΔT = C V² /2
=> V = √[2 m s ΔT / C]
kvnmurty:
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Answered by
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Answer:
The electrical potential energy stored in the capacitor is = C V² /2
This energy is dissipated in the circuit through the resistance wire. That heat is absorbed by the insulated block. Apply conservation of energy :
Heat absorbed = m s ΔT = C V² /2
=> V = √[2 m s ΔT / C]
Explanation:
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