Math, asked by 160467, 3 months ago


24. A hall is 10 m long, 5 m wide and 4 m high. It
has one door 2 m by 1 m and 2 windows 1 m by
80 cm. Find the
(i) area of the 4 walls (excluding the door and
windows)
(ii) cost of distempering the walls at 50 per m^2
(iii) cost of polishing the floor at the rate of 5 per m^3 .​

Answers

Answered by Anonymous
1

Answer:Answer

2.0/5

1

bhagyashreechowdhury

The cost of whitewashing it's four walls at Rs. 4.40 per sq m is 652.08 m².

Step-by-step explanation:

Step 1:

The length of the room, l = 10 m

The breadth of the room, b = 8 m

The height of the room, h = 4.5 m

∴ Area of the walls of the room including the doors and windows = 2h[l+b] = 2*4.5 [10+8] = 162 m² …… (i)

Step 2:

It is given that,

Dimensions of two doors = 2 m x 1.2 m each

So, Area of 2 doors = 2 * [l*b] = 2 * 2 * 1.2 = 4.8 m² ….. (ii)

And,

Dimensions of three windows = 2.5 m x 1.8 m each

So, Area of 3 windows = 2 * [l*b] = 2 * 2.5 * 1.8 = 9 m² ….. (iii)

Step 3:

From (i), (ii) & (iii), we get

Area of 4 walls excluding the doors and windows is,

= [Area of the walls of the room including the doors and windows] – [Area of 2 doors] – [Area of 3 windows]

= 162 – 4.8 – 9

= 148.2 m²

The cost of whitewashing the four walls of the room is given as = Rs 4.40 per sq m

Thus,

The cost of whitewashing the four walls of the room (excluding the doors and windows) is,

= 148.2 * Rs. 4.40

= Rs. 652.08

Step-by-step explanation:

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