Question

24. A man bought 10 litres of pure milk and added
5 litres of water to it but spilt 2 litres of the mixture. Of
the remaining mixture, he sold 3 litres, and again
added 2 litres of water to the remaining quantity. Find
the percentage of milk in the final mixture.
(A) 56%
(B) 55.55%
(C) 56.5%
(D) Cannot be determined​

Answer 1

Answer:

56.5 %

Step-by-step explanation:

Because he dropping

Answer 2

The percentage of milk in the final mixture is 55.55% and option (B) is correct.

Step-by-step explanation:

Given:

10 liters of pure milk and added 5 liters of water

Split 2 liters of the mixture

Sold 3 liters

Added 2 liters of water to the remaining quantity.

To Find:

The percentage of milk in the final mixture.

Solution:

As given,10 liters of pure milk and added  5 liters of water.

Pure milk quantity=10 liters   and  Water  quantity= 5 liters

Mixture quantity =Milk+water=10+5=15 liters

Milk :Water =10:5=2:1

Milk quantity in 15 liters mixture=

As given,Split 2 liters of the mixture.

Remaining mixture quantity= 15-2= 13 liters.

As given,Sold 3 liters.

Remaining mixture quantity= 13-3= 10 liters.

Milk :Water =2:1

Quantity of milk in remaining mixture 10 liters $=10\times\frac{2}{3} =\frac{20}{3}$ liters.

Quantity of water in remaining mixture  10 liters $=10\times\frac{1}{3} =\frac{10}{3}$ liters

As given,added 2 liters of water to the remaining quantity.

Final mixture quantity= 10+2=12 liters

Quantity of milk in final mixture 12 liters $=\frac{20}{3}$ liters.

Quantity of water in final mixture 12 liters $=\frac{10}{3}+2=\frac{16}{3}$ liters

12 liters final mixture,  $\frac{20}{3}$ the quantity of milk.

Therefore,the percentage of milk in the final mixture $=\frac{20\times 100}{3\times 12} =55.55\%$

Thus,the percentage of milk in the final mixture is 55.55% and option (B) is correct.

#SPJ2