Math, asked by subhadipbharari74, 8 months ago

24. A thief steals a car at 1.30 p.m. and drives it at 40 km/hr. The theft is discovered at 2 p.m. and the owner sets off 0.
another car at 50 km/hr. He will overtake the thief at-
a) 4 p.m.
b) 6 p.m.
c) 4:30 p.m.
d) 6.30 p.m.​

Answers

Answered by yogitakambleyk19
0

Answer:

d. 6. 30 p.m.

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Answered by sshailshetty
7

Answer:

The owner will overtake the thief at 4 pm

Step-by-step explanation:

⇉Distance covered by the thief in (2p.m.-1:30p.m)=1/2

⇉Hr at speed of 40km/hr

40 \times  \frac{1}{2}  = 20kms

⇉Their relative speed in same direction....

⇉(50-40)=10 km/hr

According Question....

20km,is the distance that has to be covered by the owner to catch theif....

⇉Required Time..

 \frac{20km}{10km \: hr}  = 2hours

Therefore he will catch the thief at...

⇉2p.m.+2hr=4p.m.

Hence The owner will catch the thief at 4 p.m.

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