Question

24. A uniform metal chain is placed on a rough table such that one end of chain hangs down over the edge of the
table. When one - third of its length hangs over the edge, the chain starts sliding. Then, the coefficient of
static friction is
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Answer 1

$\huge\underline\mathfrak\red{Answer}$

WHAT THIS QUESTION MEAN ACTUALLY....

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$length \: of \: the \: chain \: = l \\ mass \: of \: chain = m \\ \\ mass \: distributed \: along \: length \: \frac{l}{3} \\ = \frac{m}{3} \\ \\ mass \: \: on \: wedge = m - \frac{m}{3} \\ \\ mass \: on \: wedge = \frac{2m}{3} \\ \\ force \: pulling \: chain \: downward = \frac{mg}{3} \\ \\ as \: the \: body \: just \: start \: \: force \: of \: \\ so \: friction \: force \: is \: enough \: to \: \\ hold \: the \: part \: of \: chain \: hanging \\ \\ \gamma = coefficient \: of \: friction \\ \\ normal \: force \: acting \: on \: the \: chain \\ on \: the \: table = \frac{2mg}{3} \\ \\ frictional \: force = \frac{2mg \gamma }{3} \\ \\ frictional \: force = force \: pulling \: downwards \\ \\ \frac{2mg \gamma }{3} = \frac{mg}{3} \\ \\ \gamma = 0.5$