Question

24. A wire is bent to form a square of side 15 cm. If this wire is reshaped to form a rectangle of
length 20 cm, find the:
(a) Perimeter of the rectangle.
(b) Breadth of the rectangle.​

Answer 1

Answer:

(a) primeter = 60 cm

(b) breadth = 10 cm

Step-by-step explanation:

side of square = 15

perimeter of square = 15 × 4 = 60 cm

length of rectangle = 20 cm

let breadth be x

perimeter of square = perimeter of rectangle

perimeter of rectangle = 60 cm

2 × (l+b) = 60

2 × (20+x) = 60

20+x = 60/2

20 +x = 30

x = 30 - 20

x = 10 cm

Answer 2

Greetings of the day !

Let us start solving  the problem in a step-by-step simple fashion without further ado :-

SOLUTION

Given, the wire has been bent to form a square of side 15 cm.

This is means that the sum of all sides of the square(i.e perimeter) is equal to the total length of wire.

So, Perimeter of square = 4 × side

                                        = (4 × 15) cm

                                        = 60 cm

                                        = length of wire

Again, the wire is reshaped into a rectangle of length(l) 20 cm.

Let the breadth of the rectangle be b cm.

So, perimeter of square must be equal to perimeter of rectangle [since they are formed from the same wire]

(a) ∴ Perimeter of the rectangle = 60 cm

⇒ Perimeter of square = Perimeter of rectangle

⇒ 60 = 2 ( l + b )

⇒ 60/2 = l + b

⇒30 = 20 + b [ l = 20 cm given ]

⇒b = 30 - 20

Hence, (b) Breadth(b) of rectangle = 10 cm

ANSWER

Perimeter of rectangle = 60 cm

Breadth of rectangle = 10 cm

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Hope you find this answer satisfactory and self-explanatory. And if you do, please feel free to express your gratitude ;)

PEACE !!