24 A wire of length 86 cm is bent in the form of a rectangle such that its length is 7 cm more
than its breadth. Find the length and the breadth of the rectangle so formed.
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Solution,
Total length of the wire = 86 cm = Perimeter of rectangle
Shape to which it is bent = Rectangle
Given,
Breadth = x
Length = 7 + x
Perimeter = 2 (l + b)
86 cm = 2 (7 + x + x)
86 cm = 2 (7 + 2x)
86 cm = 14 + 2x
86 - 14 = 2x
72 = 2x
Therefore
x = 72/2
x = 36 cm
Breadth = x = 36 cm
Length = 7 + x = 36 + 7 = 43 cm
Therefore,
Breadth = 36 cm
Length = 43 cm
Knowledge Bytes:
→ Rectangle
A rectangle is a closed polygon made up of four line segments. The opposite pair of line segments are equal and parallel. All the angles are right angled in a rectangle.
→ Perimeter of a rectangle
2 (l + b)
→ Area of a rectangle
lb
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