24. An elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10 m above
the ground level, how long will it take to reach -350 m?
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speed: 6m/min
starting point is 10 m above the ground
as it has to go 10 m downwards we will mark it as -10 m
he has to reach a point at -350 m
total distance to be covered is -350+(-10)
= -350 - 10
= -360
time = distance/speed
= -360/6
= 60 minutes
though the answer would be - 60 minutes
but as time can never be in negatives
we will denote it as 60 minutes
60 minutes = 1 hour
- the shaft will take 1 hour to cover the whole distance
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