24 and 25. no. questions
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Suppose 32 grams of each gas is taken in the container.
Therefore moles Oxygen gas
=32/32=1
Moles of Hydrogen gas
=32/2=16
Moles of Methane Gas
=32/16=2
Now from Gay Lusaac's Law of constant volume, we know that volume ratio is same as molar ratio.
Therefore volume ratio is
1:16:2
:)
Therefore moles Oxygen gas
=32/32=1
Moles of Hydrogen gas
=32/2=16
Moles of Methane Gas
=32/16=2
Now from Gay Lusaac's Law of constant volume, we know that volume ratio is same as molar ratio.
Therefore volume ratio is
1:16:2
:)
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