Question

24. Area of triangle formed by (1, -4), (3,-2) and (-3, 16) is​

Answer 1

here your answer and please mark it brainlist

Answer 2

Hello !!

Has a method very simple for you answer this question, is you make use of this afirmation.

"The area of a triangle can be obtained with half the modulus of its vertex determinant".

$\left[\begin{array}{ccc}1&-4&1\\3&-2&1\\-3&16&1\end{array}\right]\begin{array}{cc}-1&4\\3&-2\\-3&16\end{array}$

Calculate the determinant.

Det = -2 + 12 + 48 - 6 - 16 + 12

Det = -2 + 12 + 48 - 6 - 4

Det = -2 + 12 + 48 - 10

Det = -2 + 12 + 38

Det = -2 + 50

Det = -48

Now , you find the area.

$\mathsf{A=\dfrac{|Det|}{2}} \\\\\\ \mathsf{A=\dfrac{|-48|}{2}} \\\\\\ \boxed{\mathsf{A=24~ua}}$

Final result : 24 ua.

I hope I have collaborated !