Question

24. Calculate the amount of glucose required for preparing 500mL of 0.1M solution. IT​

Answer 1

Answer:

we know that molarity=given moles of solute÷total volume of solution in liters ,

0.1=n solute÷500/1000

0.1=n solute/0.5l

0.1×0.5=n solute

0.05moles=solute

now weight of solute =give moles ×gram atomic mass of solute

=0.05×180(gram atomic mass of glucose)

=9ml of gulcose