24. Cards are marked with numbers from 10 to
50 and well shuffled. One card is drawn at
random. What is the probability that it is a
number
(i) divisible by 5 (ii) a perfect square
(iii) a multiple of 3 and 4
(iv) with one of the digits 5
Answers
Total number of cards (from 10 to 50) = 40
Total number of possible outcomes = Total number of cards = 40
i.) divisible by 5
Numbers of cards which are divisible by 5 are 9 (i.e. 10, 15, 20, 25, 30, 35, 40, 45 and 50)
Number of favourable outcomes = Numbers of cards which are divisible by 5 = 9
ii.) a perfect square
Numbers of cards which are a perfect square are 4 (i.e. 16, 25, 36, and 49)
Number of favourable outcomes = Numbers of cards which are a perfect square = 4
iii.) a multiple of 3 and 4
Numbers of cards which are a multiple of 3 and 4 are 19(i.e. 12, 15, 16, 18, 20, 21, 24, 27, 28, 30, 32, 33, 36, 39, 40, 42, 44, 45 and 48)
Number of favourable outcomes = Numbers of cards which are a multiple of 3 and 4 = 19
iv.) with one of the digits 5
Numbers of cards with one of the digits 5 are 5 (i.e. 15, 25, 35, 45 and 50)
Number of favourable outcomes = with one of the digits 5 = 5
Answer:
Step-by-step explanation:
(i) no divisible by 5=10,15,20,25,30,35,40,45,50
No are: 10,Total=50-10+1=41
P =10/41
(ii) 12,24,36,48
P=4/41
(III)
15,25,35,45,50
P=5/41